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Milwaukee Named Drunkest City In America

According to The Daily Beast, Milwaukee is the drunkest city in America:

Just in time for New Year’s Eve, Milwaukee is named the “Drunkest City in America.” That’s according to a list compiled by a website called The Daily Beast.

A recent national student shows Milwaukee adults take down more drinks than any other city in the country. On average, they drank nearly 13 alcoholic drinks a month. And according to “The Daily Beast,” 21.8% of those adults are considered binge drinkers.

“The Daily Beast” says it compared three factors when compiling the list. They include average alcohol consumption per month, binge drinking levels, and the rate of death related to alcoholic liver disease.

Rounding out the top five drunkest cities are Fargo, San Francisco, Austin and Reno.

The rest of the top ten were:

6. Burlington, Vermont

7. Omaha, Nebraksa

8. Boston, Massachusetts

9. Anchorage. Alaska

10. San Diego, California

Among other American cities, Philadelphia came in at No. 20, Chicago came in at No. 29, and Las Vegas is at No. 36. Neither New York City nor Washington, D.C. made the top 40.

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About Doug Mataconis
Doug holds a B.A. in Political Science from Rutgers University and J.D. from George Mason University School of Law. He joined the staff of OTB in May, 2010 and also writes at Below The Beltway. Follow Doug on Twitter | Facebook

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  1. Mama must be so proud!

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