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## Homework Statement

Jack plays a game with two fair spinners, A and B. Spinner A can land on the number 2 or 3 or 5 or 7

Spinner B can land on the number 2 or 3 or 4 or 5 or 6

Jack spins both spinners.

He wins the game if one spinner lands on an odd number and the other spinner lands on an even number.

Jack plays the game twice.

Work out the probability that Jack wins the game both times

**3. The Attempt at a Solution**

If you do a probability tree diagram...

I get (1/4 x 2/5) + (3/4x3/5)^3 = 0.191125 That's for the first time he plays.

But then playing twice keeps the same probability, right? If not, why?

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